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7x^2-644=0
a = 7; b = 0; c = -644;
Δ = b2-4ac
Δ = 02-4·7·(-644)
Δ = 18032
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{18032}=\sqrt{784*23}=\sqrt{784}*\sqrt{23}=28\sqrt{23}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-28\sqrt{23}}{2*7}=\frac{0-28\sqrt{23}}{14} =-\frac{28\sqrt{23}}{14} =-2\sqrt{23} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+28\sqrt{23}}{2*7}=\frac{0+28\sqrt{23}}{14} =\frac{28\sqrt{23}}{14} =2\sqrt{23} $
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